列表(List)、映射(Dict)、集合(Set)是python的三种基本数据结构,日常的工作中需要熟练掌握它们的基本操作函数
List
添加元素
尾部添加元素:append
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| >>> l = [1,2,3] >>> l.append(4) >>> l [1, 2, 3, 4]
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指定位置添加元素:insert(index从0开始)
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| >>> l = [1,2,3] >>> l.insert(2, 4) >>> l [1, 2, 4, 3]
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列表尾部添加另一个列表(extend)
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| >>> l1 = [1,2,3] >>> l2 = [4,5,6] >>> l1.extend(l2) >>> l1 [1, 2, 3, 4, 5, 6]
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将列表元素按某个分隔符拼接到一起(join)
1 2
| >>> '_'.join(['a', 'b', 'c']) 'a_b_c'
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列表推导
遍历列表然后进行一定的变换(过滤、映射)是常见操作,如果先创建一个列表来存放遍历时产生的新元素当然可以,但是代码比较冗余不够”pythonic”,比如现在要遍历0-9然后过滤出偶数:
常规写法:
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| >>> l1 = range(10) >>> l2 = [] >>> for x in l1: ... if x % 2 == 0: ... l2.append(x) ... >>> l2 [0, 2, 4, 6, 8]
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列表推导写法:
1 2 3
| >>> l = range(10) >>> [x for x in l if x%2 == 0] [0, 2, 4, 6, 8]
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for-loop
遍历列表同时获得对应index
1 2 3 4 5 6
| >>> for index, item in enumerate(['a', 'b', 'c']): ... print(index, item) ... (0, 'a') (1, 'b') (2, 'c')
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同时遍历两个列表(zip)
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| >>> a = [1,2,3] >>> b = [4,5,6] >>> for x, y in zip(a,b): ... print(x, y) ... (1, 4) (2, 5) (3, 6)
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Map
默认给key赋值,在for循环时代码会比较干净
常规写法:
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| >>> m = {} >>> if 'a' in m: ... m['a'] += 10 ... else: ... m['a'] = 10 ... >>> m {'a': 10}
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defaultdict写法:
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| >>> from collections import defaultdict >>> m = defaultdict(lambda: 0) >>> m['a'] += 10 >>> print(m) defaultdict(<function <lambda> at 0x109b99668>, {'a': 10})
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按值排序
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| >>> m = {'a': 1, 'b': 3, 'c': 2} >>> x = sorted(m.items(), key = lambda x: x[1]) >>> x [('a', 1), ('c', 2), ('b', 3)]
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Set
并集
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| >>> s1 = set(['a', 'b', 'c']) >>> s2 = set(['a', 'b', 'd']) >>> s1.union(s2) set(['a', 'c', 'b', 'd']) >>> s1 | s2 set(['a', 'c', 'b', 'd'])
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交集
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| >>> s1 = set(['a', 'b', 'c']) >>> s2 = set(['a', 'b', 'd']) >>> s1.intersection(s2) set(['a', 'b']) >>> s1 & s2 set(['a', 'b'])
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差集
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| >>> s1 = set(['a', 'b', 'c']) >>> s2 = set(a--- title: Python集合操作 date: 2022-02-03 12:25:30 tags: categories: [Python] --- **列表(List)、映射(Dict)、集合(Set)是python的三种基本数据结构,日常的工作中需要熟练掌握它们的基本操作函数** <!--more-->
<br>
**尾部添加元素:append** ```Python >>> l = [1,2,3] >>> l.append(4) >>> l [1, 2, 3, 4]
|
指定位置添加元素:insert(index从0开始)
1 2 3 4
| >>> l = [1,2,3] >>> l.insert(2, 4) >>> l [1, 2, 4, 3]
|
列表尾部添加另一个列表(extend)
1 2 3 4 5
| >>> l1 = [1,2,3] >>> l2 = [4,5,6] >>> l1.extend(l2) >>> l1 [1, 2, 3, 4, 5, 6]
|
将列表元素按某个分隔符拼接到一起(join)
1 2
| >>> '_'.join(['a', 'b', 'c']) 'a_b_c'
|
列表推导
遍历列表然后进行一定的变换(过滤、映射)是常见操作,如果先创建一个列表来存放遍历时产生的新元素当然可以,但是代码比较冗余不够”pythonic”,比如现在要遍历0-9然后过滤出偶数:
常规写法:
1 2 3 4 5 6 7 8
| >>> l1 = range(10) >>> l2 = [] >>> for x in l1: ... if x % 2 == 0: ... l2.append(x) ... >>> l2 [0, 2, 4, 6, 8]
|
列表推导写法:
1 2 3
| >>> l = range(10) >>> [x for x in l if x%2 == 0] [0, 2, 4, 6, 8]
|
for-loop
遍历列表同时获得对应index
1 2 3 4 5 6
| >>> for index, item in enumerate(['a', 'b', 'c']): ... print(index, item) ... (0, 'a') (1, 'b') (2, 'c')
|
同时遍历两个列表(zip)
1 2 3 4 5 6 7 8
| >>> a = [1,2,3] >>> b = [4,5,6] >>> for x, y in zip(a,b): ... print(x, y) ... (1, 4) (2, 5) (3, 6)
|
Map
默认给key赋值,在for循环时代码会比较干净
常规写法:
1 2 3 4 5 6 7 8 9
| >>> m = {} >>> if 'a' in m: ... m['a'] += 10 ... else: ... m['a'] = 10 ... >>> m {'a': 10}
|
defaultdict写法:
1 2 3 4 5
| >>> from collections import defaultdict >>> m = defaultdict(lambda: 0) >>> m['a'] += 10 >>> print(m) defaultdict(<function <lambda> at 0x109b99668>, {'a': 10})
|
按值排序
1 2 3 4
| >>> m = {'a': 1, 'b': 3, 'c': 2} >>> x = sorted(m.items(), key = lambda x: x[1]) >>> x [('a', 1), ('c', 2), ('b', 3)]
|
Set
并集
1 2 3 4 5 6
| >>> s1 = set(['a', 'b', 'c']) >>> s2 = set(['a', 'b', 'd']) >>> s1.union(s2) set(['a', 'c', 'b', 'd']) >>> s1 | s2 set(['a', 'c', 'b', 'd'])
|
交集
1 2 3 4 5 6
| >>> s1 = set(['a', 'b', 'c']) >>> s2 = set(['a', 'b', 'd']) >>> s1.intersection(s2) set(['a', 'b']) >>> s1 & s2 set(['a', 'b'])
|
差集
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| >>> s1 = set(['a', 'b', 'c']) >>> s2 = set(['a', 'b', 'd']) >>> s1.difference(s2) set(['c']) >>> s1 - s2 set(['c']) ```['a', 'b', 'd']) >>> s1.difference(s2) set(['c']) >>> s1 - s2 set(['c'])
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